12x^2+120x=0

Solution for 12x^2+120x=0 equation:

12x^2+120x=0

a = 12; b = 120; c = 0;
Δ = b2-4ac
Δ = 1202-4·12·0
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-120}{2*12}=\frac{-240}{24}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+120}{2*12}=\frac{0}{24}
=0
$